Let $\mathfrak{a}\subseteq A$ be an ideal of a ring $A$. If $r(\mathfrak{a})=\mathfrak{m}$ is maximal, then 1;;$\mathfrak{a}$ is $\mathfrak{m}$-primary. In particular, if $\mathfrak{m}$ is maximal, then ${\mathfrak{m}}^i$ is $\mathfrak{m}$-primary for each $i\in \mathbb{N}$