Here are some examples to show that the case of holomorphic functions really is a special case.

  1. Notice that if we let fn(z)=zn, then this function only has one zero, but the limit is equal to 0.
  2. Consider the real numbers, and a function of the kind fn(x)=x2+1n. these functions have no zeros, because this is an irreducible polynomial. But it's limit is x2 which has two zeros.
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